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प्रश्न
Solve for x : ` 2x^2+6sqrt3x-60=0`
उत्तर
Consider the given equation:
`2x^2+6sqrt3x-60=0`
`x^2+3sqrt3-30=0`
Let us the quadratic formula to find x.
`x=(-b+-sqrt(b^2-4ac))/(2a)`
Here, a = 1, b = 3√3 and c =-30
Thus,
`x=(-3sqrt3+-sqrt((3sqrt3)^2-4xx1xx(-30)))/(2xx1)`
`x=(-3sqrt3+-sqrt(27+120))/2`
`x=(-3sqrt3+-sqrt147)/2`
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