Question

For a one dimensional electric field, the correct relation of E and potential V is _________.

पर्याय

• E = `("d"^2"V")/"dx"^2`

• E = - `"dV"/"dx"`

• E = `"dV"/"dx"`

• E = - `("d"^2"V")/"dx"^2`

Answer 1

For a one dimensional electric field, the correct relation of E and potential V is `underline("E" = - "dV"/"dx")`.

Explanation:

The negative gradient of the potential is defined as the electric field. In the direction of the electric field, the potential drops.

E = - `"dV"/"dx"`