Advertisements
Advertisements
Question
For a one dimensional electric field, the correct relation of E and potential V is _________.
Options
E = `("d"^2"V")/"dx"^2`
E = - `"dV"/"dx"`
E = `"dV"/"dx"`
E = - `("d"^2"V")/"dx"^2`
MCQ
Fill in the Blanks
Solution
For a one dimensional electric field, the correct relation of E and potential V is `underline("E" = - "dV"/"dx")`.
Explanation:
The negative gradient of the potential is defined as the electric field. In the direction of the electric field, the potential drops.
E = - `"dV"/"dx"`
shaalaa.com
The Parallel Plate Capacitor
Is there an error in this question or solution?
