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प्रश्न
Give simple chemical tests to distinguish between the following pair of compounds:
Benzaldehyde and Benzoic acid
Give simple chemical test to distinguish between Benzoic acid and Benzaldehyde.
उत्तर १
Through sodium bicarbonate:
Benzaldehyde does not react with sodium bicarbonate. However, benzoic acid will produce brisk effervescence in reaction with sodium bicarbonate, as shown in the given reaction:
\[\ce{C6H5COOH + NaHCO3 -> C6H5COO^-Na+ + CO2 ↑ + H2O}\]
\[\ce{C6H5CHO ->[NaHCO3 solution] No effervescene}\]
Through Tollen's reagent:
Benzaldehyde reacts with an ammonia solution of silver nitrate to form a silver mirror.
\[\ce{C6H5CHO + 2[Ag(NH3)2]+ + 3OH^- -> C6H5COO^- + 2Ag + 2H2O + 4NH3}\]
However, no such reaction is given by benzoic acid.
उत्तर २
Benzoic acid reacts with ethanol in the presence of dilute sulphuric acid to form sweet-smelling ester Ethyl benzoate. This reaction is not given by benzaldehyde.
Notes
Students can refer to the provided solutions based on their preferred marks.
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संबंधित प्रश्न
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
(CH3CH2)2NCH3
Give one chemical test to distinguish between the following pair of compounds.
Secondary and tertiary amines
Account for the following:
pKb of aniline is more than that of methylamine.
How will you convert methanamine into ethanamine?
How will you convert nitromethane into dimethylamine?
Accomplish the following conversion:
Benzoic acid to aniline
Accomplish the following conversion:
Aniline to benzyl alcohol
Write the IUPAC name of the given compound :
Identify the incorrect IUPAC name.
An organic compound (A) with molecular formula C3H7NO on heating with Br2 and KOH forms a compound (B). Compound (B) on heating with CHCl3 and alcoholic KOH produces a foul-smelling compound (C) and on reacting with C6H5SO2Cl forms a compound (D) which is soluble in alkali. Write the structure of (A), (B), (C) and (D).
