Advertisements
Advertisements
प्रश्न
How many terms are there in the AP 6,1 0, 14, 18, ….., 174?
उत्तर
In the given AP, a = 6 and d = (10-6) = 4
Suppose that there are n terms in the given AP.
Then, `T_n = 174 `
⇒ a+ (n-1) d =174
⇒ 6+ (n-1) × 4 = 174
⇒ 2+ 4n = 174
⇒ 4n = 172
⇒ n= 43
Hence, there are 43 terms in the given AP.
APPEARS IN
संबंधित प्रश्न
Fill in the blank in the following table, given that a is the first term, d the common difference, and an nth term of the AP:
a | d | n | an |
7 | 3 | 8 | ______ |
Find:
(i) the 20th term of the AP 9,13,17,21,..........
If sum of 3rd and 8th terms of an A.P. is 7 and sum of 7th and 14th terms is –3 then find the 10th term.
Next term of the AP `sqrt2, 3sqrt2, 5sqrt2,...` is ______.
The (n - 1)th term of an A.P. is given by 7, 12, 17, 22,… is ______.
The nth term of an A.P. 5, 2, -1, -4, -7 … is ______.
The 10th term from the end of the A.P. -5, -10, -15,…, -1000 is ______.
For the AP: –3, –7, –11, ..., can we find directly a30 – a20 without actually finding a30 and a20? Give reasons for your answer.
Is 0 a term of the AP: 31, 28, 25, ...? Justify your answer.
Justify whether it is true to say that the following are the nth terms of an AP.
3n2 + 5