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प्रश्न
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
लघु उत्तर
उत्तर
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Describe the lines of latitude, their importance, and use.
What is the relation between Temperature and Latitude of a place?
What is latitude of North pole and South pole?
Define the Equator. What is its main function?
Parallels and meridians are imaginary lines.
Using a globe, write down the names of the countries through which the equator passes.
Complete the following table.
| Characteristics | Parallels of latitude | Meridians of longitude |
| Shape | ||
| Size | Size of each parallel is different. | |
| Distance | Distance between two meridians is larger on the equator and the same decreases towards the Poles. |
Name the four hemispheres of the Earth.
The regions on Earth between North & South lines of latitude (66 ½°) and poles (90°) is called Frigid Zone.
Write a note Latitudes.
