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Question
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
Short Answer
Solution
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
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