Advertisements
Advertisements
प्रश्न
If `sqrt (2/3)` is a solution of equation 3x2 + mx + 2 = 0, find the value of m.
उत्तर
For x = `sqrt (2/3)` to be solution of the given quadratic equation it should satisfy the equation
So, substituting x = `sqrt (2/3)` in the given equation, we get
`3(sqrt (2/3))^2 + m(sqrt (2/3)) + 2 = 0`
`\implies 3(2/3) + m(sqrt (2/3)) + 2 = 0`
`\implies m = -4 sqrt (3/2) = -2sqrt6`
∴ `m = -2sqrt6`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by factorization method : `3x^2-29x+40=0`
Solve the following quadratic equations by factorization:
4x2 + 5x = 0
Divide 29 into two parts so that the sum of the squares of the parts is 425.
Sum of two numbers is 16. The sum of their reciprocals is 1/3. Find the numbers.
A takes 10 days less than the time taken by B to finish a piece of work. If both A and B together can finish the work in 12 days, find the time taken by B to finish the work.
Solve the following quadratic equations by factorization: \[\frac{16}{x} - 1 = \frac{15}{x + 1}; x \neq 0, - 1\]
Write the condition to be satisfied for which equations ax2 + 2bx + c = 0 and \[b x^2 - 2\sqrt{ac}x + b = 0\] have equal roots.
Solve the following equation: a2b2x2 + b2x - a2x - 1 = 0
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
A school bus transported an excursion party to a picnic spot 150 km away. While returning, it was raining and the bus had to reduce its speed by 5 km/hr, and it took one hour longer to make the return trip. Find the time taken to return.
