Advertisements
Advertisements
प्रश्न
If 2x + y = 23 and 4x - y = 19; find the values of x - 3y and 5y - 2x.
उत्तर
2x + y = 23 ...(1)
4x - y = 19 ...(2)
Adding equation (1) and (2) we get,
2x + y = 23
+ 4x - y = 19
6x = 42
x = 7
From (1)
2x + y = 23
⇒ 2(7) + y = 23
⇒ 14 + y = 23
⇒ y = 23 - 14
y = 9
∴ x - 3y = 7 - 3(9) = -20
and 5y - 2x = 5(9) - 2(7) = 45 - 14 = 31.
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients:
y = 2x - 6; y = 0
Solve for x and y :
`[ y + 7 ]/5 = [ 2y - x ]/4 + 3x - 5`
`[ 7 - 5x ]/2 + [ 3 - 4y ]/6 = 5y - 18`
Find the value of m, if x = 2, y = 1 is a solution of the equation 2x + 3y = m.
Solve the following simultaneous equations :
6x + 3y = 7xy
3x + 9y = 11xy
Solve the following simultaneous equations :
2(3u - v) = 5uv
2(u + 3v) = 5uv
Solve the following simultaneous equations:
65x - 33y = 97
33x - 65y = 1
Solve the following pairs of equations:
`(3)/(2x) + (2)/(3y)` = 5
`(5)/x - (3)/y` = 1
The sum of the numerator and denominator of a fraction is 12. If the denominator is increased by 3, the fraction becomes `(1)/(2)`. Find the fraction.
If 1 is added to the denominator of a fraction, the fraction becomes `(1)/(2)`. If 1 is added to the numerator of the fraction, the fraction becomes 1. Find the fraction.
Two mobiles S1 and S2 are sold for Rs. 10,490 making 4% profit on S1 and 6% on S2. If the two mobiles are sold for Rs.10,510, a profit of 6% is made on S1 and 4% on S2. Find the cost price of both the mobiles.