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प्रश्न
If A2 + 5A + 3I = 0, |A| ≠ 0, then A–1 = ______
पर्याय
`(-1)/3 ("A" + 5"I")`
`(-1)/5 ("A" + 3"I")`
(A + 15I)
`(-1)/3 ("I" + 5"A")`
उत्तर
If A2 + 5A + 3I = 0, |A| ≠ 0, then A–1 = `bbunderline((-1)/3 ("A" + 5"I"))`
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