Question

If ax⁴ + bx³ + cx² + dx + e = `|(2x, x - 1, x + 1),(x + 1, x^2 - x, x - 1),(x - 1, x + 1, 3x)|`, then the value of e is ______.

पर्याय

• 0

• –2

• 3

• –1

Answer 1

If ax⁴ + bx³ + cx² + dx + e = `|(2x, x - 1, x + 1),(x + 1, x^2 - x, x - 1),(x - 1, x + 1, 3x)|`, then the value of e is 0.

Explanation:

ax⁴ + bx³ + cx² + dx + e = `|(2x, x - 1, x + 1),(x + 1, x^2 - x, x - 1),(x - 1, x + 1, 3x)|`

Put x = 0 both sides

e = `|(0, -1, 1),(1, 0, -1),(-1, 1, 0)|` = 0 ...(Skew symmetric)

∴ e = 0