मराठी

If f(x)=1x-1, g(x)=1(x+1)(x-1), then the number of integers which are not in domian of gof(x) are -

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प्रश्न

If `f(x) = 1/(x - 1)`, `g(x) = 1/((x + 1)(x - 1))`, then the number of integers which are not in domian of gof(x) are

पर्याय

  • 0

  • 1

  • 2

  • more than 2

MCQ

उत्तर

more than 2

Explanation:

`gof(x) = gf(x) = g(1/(x - 1))x ≠ 1`

= `((-1)/2) = (x - 1)^2/(x(2 - x)), x ≠ 0.2`

Domain R – {0, 1, 2}

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