Question

If `f(x) = 1/(x - 1)`, `g(x) = 1/((x + 1)(x - 1))`, then the number of integers which are not in domian of gof(x) are

Options

• 0

• 1

• 2

• more than 2

Answer 1

more than 2

Explanation:

`gof(x) = gf(x) = g(1/(x - 1))x ≠ 1`

= `((-1)/2) = (x - 1)^2/(x(2 - x)), x ≠ 0.2`

Domain R – {0, 1, 2}