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प्रश्न
If tan 4θ = `tan(2/θ)`, then the general value of θ is ______.
पर्याय
`(nπ ± sqrt(n^2π^2 + 32))/8`
`(nπ ± sqrt(n^2 + 32))/8`
`(nπ ± sqrt(π^2 + 32))/8`
`(nπ ± sqrt(n^2 + 32))/16`
MCQ
रिकाम्या जागा भरा
उत्तर
If tan 4θ = `tan(2/θ)`, then the general value of θ is `underlinebb((nπ ± sqrt(n^2π^2 + 32))/8)`.
Explanation:
tan 4θ = `tan(θ/2)`
∴ 4θ = `nπ + 2/θ`
∴ 4θ2 – nπθ – 2 = 0
∴ θ = `(nπ ± sqrt(n^2π^2 + 32))/8`
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