Question

If temperature of black body increases from  17°C to 307°C, then the rate of radiation increases by ______.

पर्याय

• 16

• 2

• 4

• `(307/17)^4`

Answer 1

If temperature of black body increases from  17°C to 307°C, then the rate of radiation increases by 16.

Explanation:

Rate of radiation `"dQ"/"dt" prop "T"^4`

T₁ = 17°C = 273 + 17 = 290 K

T₂ = 307°C = 273 + 307 = 580 K

∴ `(("dQ"/"dt")_2)/(("dQ"/"dt")_1)`

`= (580/290)^4 = 2^2 = 16`