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प्रश्न
If the distance between the points (3, −5) and (x, −5) is 15 units, then the values of x are ______.
पर्याय
12, −18
−12, 18
18, 5
−9, −12
MCQ
रिकाम्या जागा भरा
उत्तर
If the distance between the points (3, −5) and (x, −5) is 15 units, then the values of x are −12, 18.
Explanation:
Here, (15)2 = (3 − x)2 + (−5 + 5)2
225 = 9 − 6x + x2
or, x2 − 6x − 216 = 0
or, x2 − 18x + 12x − 216 = 0
or, x (x − 18) + 12 (x − 18) = 0
or, (x − 18) (x + 12) = 0
or, x = − 12, 18
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