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If the line y = 4x – 5 touches the curves y2 = ax3 + b at the point (2, 3), find a and b. - Mathematics and Statistics

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प्रश्न

If the line y = 4x – 5 touches the curves y2 = ax3 + b at the point (2, 3), find a and b.

बेरीज

उत्तर

y2 = ax3 + b

Differentiating both sides w.r.t. x, we get

`2ydy/dx = a xx 3x^2 + 0`

∴ `dy/dx = (3ax^2)/(2y)`

∴ `(dy/dx)_("at" (2, 3)) = (3a(2)^2)/(2(3))`

= 2a

= slope of the tangent at (2, 3)

Since, the line y = 4x – 5 touches the curve at the point (2, 3), slope of the tangent at (2, 3) is 4.

∴ 2a = 4

∴ a = 2

Since (2, 3) lies on the curve y2 = ax3 + b,

(3)2 = a(2)3 + b

∴ 9 = 8a + b

∴ 9 = 8(2) + b         ...[∵ a = 2]

∴ b = – 7

Hence, a = 2 and b = – 7.

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Applications of Derivatives in Geometry
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Applications of Derivatives - Exercise 2.1 [पृष्ठ ७२]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
पाठ 2 Applications of Derivatives
Exercise 2.1 | Q 6 | पृष्ठ ७२

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