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प्रश्न
Find the slope of normal to the curve 3x2 − y2 = 8 at the point (2, 2)
उत्तर
Equation of the curve is
3x2 − y2 = 8
Differentiating w.r.t. x, we get
`6x - 2y ("d"y)/("d"x)` = 0
∴ `("d"y)/("d"x) = (3x)/y`
∴ `(("d"x)/("d"x))_((2"," 2)) = (3(2))/2`
= 3
Slope of the normal at (2, 2) is `(-1)/(("d"y)/("d"x))_((2, 2)) = (-1)/3`
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