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प्रश्न
If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.
उत्तर
Maximum molarity of CuS in an aqueous solution = Solubility of CuS in mol L−1.
If s is the solubility of CuS in mol L−1, then
\[\ce{CuS <=> Cu^{2+} + S^{2-}}\]
Ksp = [Cu2+][S2−]
= s × s
= s2
∴ s2 = 6 × 10−16 or s = `sqrt(6 xx 10^-16)`
= 2.45 × 10−8 mol L−1
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