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प्रश्न
If the solubility product of lead iodide is 3.2 × 10−8, its solubility will be ____________.
पर्याय
2 × 10−3 M
4 × 10−4 M
1.6 × 10−5 M
1.8 × 10−5 M
उत्तर
If the solubility product of lead iodide is 3.2 × 10−8, its solubility will be 2 × 10−3 M.
Explanation:
\[\ce{PbI2_{(s)} ⇌ Pb^{2+}_{( aq)} + 2I^-_{( aq)}}\]
Ksp = (s) (2s)2
3.2 × 10−8 = 4s3
s = `((3.2 xx 10^-8)/4)^(1/3)`
= `(8 xx 10^-9)^(1/3)`
= 2 × 10−3 M
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