Question

If V₀ is the volume of a given mass of gas at 273 K at a constant pressure then according to Charle's law, the volume at 10°C will be:

पर्याय

• 11 V₀

• `1/273 ("V"_0 + 10)`

• `"V"_0 + 10/273`

• `283/273 "V"_0`

Answer 1

`283/273 "V"_0`

Explanation:

According to Charles' law

V_t = `"V"_0 ((273 + "t")/273) = "V"_0 xx 283/273`