Question

If V₀ is the volume of a given mass of gas at 273 K at a constant pressure then according to Charle's law, the volume at 10°C will be:

Options

• 11 V₀

• ${\displaystyle \frac{1}{273}({\text{V}}_0+10)}$

• ${\displaystyle {\text{V}}_0+\frac{10}{273}}$

• ${\displaystyle \frac{283}{273}{\text{V}}_0}$

Answer 1

${\displaystyle \frac{283}{273}{\text{V}}_0}$

Explanation:

According to Charles' law

V_t = ${\displaystyle {\text{V}}_0\left(\frac{273+\text{t}}{273}\right)={\text{V}}_0\times \frac{283}{273}}$