Advertisements
Advertisements
प्रश्न
If `x/4 + y/3 = 15/12 and x/2 + y = 1,` then find the value of (x + y).
उत्तर
The given pair of equations is
`x/4 + y/3 = 5/12 ` ………(i)
`x/2 + y = 1` ………(ii)
Multiplying (i) by 12 and (ii) by 4, we have
3x + 4y = 5 ……….(iii)
2x + 4y = 4 ………(iv)
Now, subtracting (iv) from (iii), we get
x = 1
Putting x = 1 in (iv), we have
2 + 4y =4
⇒ 4y = 2
⇒ y =`1/2`
∴ x + y = 1 + `1/2 = 3/2 `
Hence, the value of x + y is `3/2`
APPEARS IN
संबंधित प्रश्न
Determine the values of a and b so that the following system of linear equations have infinitely many solutions:
(2a - 1)x + 3y - 5 = 0
3x + (b - 1)y - 2 = 0
Solve for x and y:
4x - 3y = 8, 6x - y = `29/3`
Solve for x and y:
`x + 6/y = 6, 3x - 8/y = 5`
Solve for x and y:
`10/(x+y) + 2/(x−y) = 4, 15/(x+y) - 9/(x−y) = -2, where x ≠ y, x ≠ -y.`
Find the values of a and b for which the system of linear equations has an infinite number of solutions:
(a – 1) x + 3y = 2, 6x + (1 – 2b)y = 6
Find the numbers such that the sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.
Taxi charges in a city consist of fixed charges per day and the remaining depending upon the distance travelled in kilometers. If a person travels 80km, he pays Rs. 1330, and for travelling 90km, he pays Rs. 1490. Find the fixed charges per day and the rate per km.
The sum of two numbers is 80. The larger number exceeds four times the smaller one by 5. Find the numbers.
A man has some hens and cows. If the number of heads be 48 and number of feet by 140. How many cows are there.
Show that the system 2x + 3y -1= 0 and 4x + 6y - 4 = 0 has no solution.
