Question

If y = sec x + x^logx, then `"dy"/"dx"` is

पर्याय

• sec x tan x + `2/x` log x · (x^logx)

• `sec^2 x + x/2 log x`

• `sec^2 x + 2/x log x`

• sec x tan x + `1/x` log x

Answer 1

sec x tan x + `2/x` log x · (x^logx)

Explanation:

y = sec x + x^logx

∴ `"dy"/"dx"` = sec x tan x + `"d"/"dx"`(x^logx)

`=> "dy"/"dx"` = sec x tan x + `2/x` log x (x^logx)