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Question
If y = sec x + xlogx, then `"dy"/"dx"` is
Options
sec x tan x + `2/x` log x · (xlogx)
`sec^2 x + x/2 log x`
`sec^2 x + 2/x log x`
sec x tan x + `1/x` log x
MCQ
Solution
sec x tan x + `2/x` log x · (xlogx)
Explanation:
y = sec x + xlogx
∴ `"dy"/"dx"` = sec x tan x + `"d"/"dx"`(xlogx)
`=> "dy"/"dx"` = sec x tan x + `2/x` log x (xlogx)
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Solution of a Differential Equation
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