मराठी

In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light of wavelength 5200 Å. The value of n for which (n + 1)th green bright band would coincide -

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प्रश्न

In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light of wavelength 5200 Å. The value of n for which (n + 1)th green bright band would coincide with nth red bright band for the same setting is ______.

पर्याय

  • n = 2

  • n = 3

  • n = 4

  • n = 5

MCQ
रिकाम्या जागा भरा

उत्तर

In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light of wavelength 5200 Å. The value of n for which (n + 1)th green bright band would coincide with nth red bright band for the same setting is n = 4.

Explanation:

λR = 6500 Å  λG = 5200 Å

`beta = (lambda"d")/"D"`

(n + 1)λG = nλ

(n + 1) × 5200 = n × 6500

`("n + 1")/"n" = 65/52`

`1/"n" = 65/52 - 1 = (65 - 52)/52 = 13/52 = 1/4`

∴ n = 4

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