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Question
In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light of wavelength 5200 Å. The value of n for which (n + 1)th green bright band would coincide with nth red bright band for the same setting is ______.
Options
n = 2
n = 3
n = 4
n = 5
MCQ
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Solution
In a biprism experiment, red light of wavelength 6500 Å was used. It was then replaced by green light of wavelength 5200 Å. The value of n for which (n + 1)th green bright band would coincide with nth red bright band for the same setting is n = 4.
Explanation:
λR = 6500 Å λG = 5200 Å
`beta = (lambda"d")/"D"`
(n + 1)λG = nλR
(n + 1) × 5200 = n × 6500
`("n + 1")/"n" = 65/52`
`1/"n" = 65/52 - 1 = (65 - 52)/52 = 13/52 = 1/4`
∴ n = 4
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