Advertisements
Advertisements
प्रश्न
In a G.P. 729, 243, 81, … find t7
उत्तर
G.P = 729, 243, 81, ….
t7 = ?
tn = arn−1, here a = 729, r = `("t"_2)/("t"_1)`
r = `243/729 = 1/3`
∴ t7 = `729(1/3)^(7-1) = 729 xx (1/3)^6`
= `729 xx 1/729`
= 1
APPEARS IN
संबंधित प्रश्न
Identify the following sequence is in G.P.?
3, 9, 27, 81, …
Identify the following sequence is in G.P.?
4, 44, 444, 4444, .....
Identify the following sequence is in G.P.?
`16, 4, 1, 1/4,...`
Write the first three terms of the G.P. whose first term and the common ratio are given below
a = 1000, r = `2/5`
Find x so that x + 6, x + 12 and x + 15 are consecutive terms of a Geometric Progression
Find the number of terms in the following G.P.
4, 8, 16, …, 8192?
In a G.P. the 9th term is 32805 and 6th term is 1215. Find the 12th term
A man joined a company as Assistant Manager. The company gave him a starting salary of ₹ 60,000 and agreed to increase his salary 5% annually. What will be his salary after 5 years?
For a GP, if Sn = `(4^"n" - 3^"n")/3^"n"`, then t2 = _______.
The sum of the first 10 terms of the series 9 + 99 + 999 + ..., is ______.
