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Question
In a G.P. 729, 243, 81, … find t7
Solution
G.P = 729, 243, 81, ….
t7 = ?
tn = arn−1, here a = 729, r = `("t"_2)/("t"_1)`
r = `243/729 = 1/3`
∴ t7 = `729(1/3)^(7-1) = 729 xx (1/3)^6`
= `729 xx 1/729`
= 1
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