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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board chapter 2 - Numbers and Sequences [Latest edition]

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Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board chapter 2 - Numbers and Sequences - Shaalaa.com
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Solutions for Chapter 2: Numbers and Sequences

Below listed, you can find solutions for Chapter 2 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Mathematics [English] Class 10 SSLC TN Board.


Exercise 2.1Exercise 2.2Exercise 2.3Exercise 2.4Exercise 2.5Exercise 2.6Exercise 2.7Exercise 2.8Exercise 2.9Exercise 2.10Unit Exercise – 2
Exercise 2.1 [Pages 42 - 43]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.1 [Pages 42 - 43]

Exercise 2.1 | Q 1 | Page 42

Find all positive integers, when divided by 3 leaves remainder 2

Exercise 2.1 | Q 2 | Page 42

A man has 532 flower pots. He wants to arrange them in rows such that each row contains 21 flower pots. Find the number of completed rows and how many flower pots are left over

Exercise 2.1 | Q 3 | Page 43

Prove that the product of two consecutive positive integers is divisible by 2

Exercise 2.1 | Q 4 | Page 43

When the positive integers a, b and c are divided by 13, the respective remainders are 9, 7 and 10. Show that a + b + c is divisible by 13

Exercise 2.1 | Q 5 | Page 43

Prove that square of any integer leaves the remainder either 0 or 1 when divided by 4

Exercise 2.1 | Q 6. (i) | Page 43

Use Euclid’s Division Algorithm to find the Highest Common Factor (H.C.F) of 340 and 412

Exercise 2.1 | Q 6. (ii) | Page 43

Use Euclid’s Division Algorithm to find the Highest Common Factor (H.C.F) of 867 and 255

Exercise 2.1 | Q 6. (iii) | Page 43

Use Euclid’s Division Algorithm to find the Highest Common Factor (H.C.F) of 10224 and 9648

Exercise 2.1 | Q 6. (iv) | Page 43

Use Euclid’s Division Algorithm to find the Highest Common Factor (H.C.F) of 84, 90 and 120

Exercise 2.1 | Q 7 | Page 43

Find the largest number which divides 1230 and 1926 leaving remainder 12 in each case

Exercise 2.1 | Q 8 | Page 43

If d is the Highest Common Factor of 32 and 60, find x and y satisfying d = 32x + 60y

Exercise 2.1 | Q 9 | Page 43

A positive integer, when divided by 88, gives the remainder 61. What will be the remainder when the same number is divided by 11?

Exercise 2.1 | Q 10 | Page 43

Prove that two consecutive positive integers are always co-prime

Exercise 2.2 [Page 46]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.2 [Page 46]

Exercise 2.2 | Q 1 | Page 46

For what value of natural number n, 4n can end with the digit 6?

Exercise 2.2 | Q 2 | Page 46

If m, n are natural numbers, for what values of m, does 2n × 5m ends in 5?

Exercise 2.2 | Q 3 | Page 46

Find the H.C.F. of 252525 and 363636

Exercise 2.2 | Q 4 | Page 46

If 13824 = 2a × 3b then find a and b

Exercise 2.2 | Q 5 | Page 46

If p1x1 × p2x2 × p3x3 × p4x4 = 113400 where p1, p2, p3, p4 are primes in ascending order and x1, x2, x3, x4, are integers, find the value of p1, p2, p3, p4 and x1, x2, x3, x4

Exercise 2.2 | Q 6 | Page 46

Find the L.C.M. and H.C.F. of 408 and 170 by applying the fundamental theorem of Arithmetic

Exercise 2.2 | Q 7 | Page 46

Find the greatest number consisting of 6 digits which is exactly divisible by 24, 15, 36?

Exercise 2.2 | Q 8 | Page 46

What is the smallest number that when divided by three numbers such as 35, 56 and 91 leaves remainder 7 in each case?

Exercise 2.2 | Q 9 | Page 46

Find the least number that is divisible by the first ten natural numbers

Exercise 2.3 [Pages 51 - 52]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.3 [Pages 51 - 52]

Exercise 2.3 | Q 1. (i) | Page 51

Find the least positive value of x such that 71 ≡ x (mod 8)

Exercise 2.3 | Q 1. (ii) | Page 51

Find the least positive value of x such that 78 + x ≡  3 (mod 5)

Exercise 2.3 | Q 1. (iii) | Page 51

Find the least positive value of x such that 89 ≡ (x + 3) (mod 4)

Exercise 2.3 | Q 1. (iv) | Page 51

Find the least positive value of x such that 96 ≡ `x/7` (mod 5)

Exercise 2.3 | Q 1. (v) | Page 51

Find the least positive value of x such that 5x ≡ 4 (mod 6)

Exercise 2.3 | Q 2 | Page 51

If x is congruent to 13 modulo 17 then 7x – 3 is congruent to which number modulo 17?

Exercise 2.3 | Q 3 | Page 51

Solve 5x ≡ 4 (mod 6)

Exercise 2.3 | Q 4 | Page 51

Solve 3x – 2 ≡ 0 (mod 11)

Exercise 2.3 | Q 5 | Page 51

What is the time 100 hours after 7 a.m.?

Exercise 2.3 | Q 6 | Page 51

What is time 15 hours before 11 p.m.?

Exercise 2.3 | Q 7 | Page 51

Today is Tuesday. My uncle will come after 45 days. In which day my uncle will be coming?

Exercise 2.3 | Q 8 | Page 51

Prove that 2n + 6 × 9n is always divisible by 7 for any positive integer n

Exercise 2.3 | Q 9 | Page 51

Find the remainder when 281 is divided by 17.

Exercise 2.3 | Q 10 | Page 52

The duration of flight travel from Chennai to London through British Airlines is approximately 11 hours. The airplane begin its journey on Sunday at 23:30 hours. If the time at Chennai is four and half hours ahead to that of London’s time, then find the time at London, when will the flight land at London Airport?

Exercise 2.4 [Page 55]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.4 [Page 55]

Exercise 2.4 | Q 1. (i) | Page 55

Find the next three terms of the following sequence.

8, 24, 72, …

Exercise 2.4 | Q 1. (ii) | Page 55

Find the next three terms of the following sequence.

5, 1, – 3, …

Exercise 2.4 | Q 1. (iii) | Page 55

Find the next three terms of the following sequence

`1/4, 2/9, 3/16, ...`

Exercise 2.4 | Q 2. (i) | Page 55

Find the first four terms of the sequence whose nth terms are given by an = n3 – 2

Exercise 2.4 | Q 2. (ii) | Page 55

Find the first four terms of the sequence whose nth terms are given by an = (–1)n+1 n(n + 1)

Exercise 2.4 | Q 2. (iii) | Page 55

Find the first four terms of the sequences whose nth terms are given by an = 2n2 – 6

Exercise 2.4 | Q 3. (i) | Page 55

Find the nth term of the following sequence

2, 5, 10, 17, ...

Exercise 2.4 | Q 3. (ii) | Page 55

Find the nth term of the following sequence

`0, 1/2, 2/3, ...`

Exercise 2.4 | Q 3. (iii) | Page 55

Find the nth term of the following sequence

3, 8, 13, 18, ...

Exercise 2.4 | Q 4. (i) | Page 55

Find the indicated terms of the sequences whose nth terms are given by

an = `(5"n")/("n" + 2)`; a6 and a13

Exercise 2.4 | Q 4. (ii) | Page 55

Find the indicated terms of the sequences whose nth terms are given by

an = – (n2 – 4); a4 and a11

Exercise 2.4 | Q 5 | Page 55

Find a8 and a15 whose nth term is an = `{{:(("n"^2 - 1)/("n" + 3)";", "n is even"","  "n ∈ N"),(("n"^2)/(2"n" + 1)";", "n is odd"","  "n ∈ N"):}`

Exercise 2.4 | Q 6 | Page 55

If a1 = 1, a2 = 1 and an = 2an−1 + an−2, n ≥ 3, n ∈ N, then find the first six terms of the sequence

Exercise 2.5 [Pages 61 - 62]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.5 [Pages 61 - 62]

Exercise 2.5 | Q 1. (i) | Page 61

Check whether the following sequence is in A.P.

a – 3, a – 5, a – 7, …

Exercise 2.5 | Q 1. (ii) | Page 61

Check whether the following sequence is in A.P.

`1/2, 1/3, 1/4, 1/5, ...`

Exercise 2.5 | Q 1. (iii) | Page 51

Check whether the following sequence is in A.P.

9, 13, 17, 21, 25, ...

Exercise 2.5 | Q 1. (iv) | Page 61

Check whether the following sequence is in A.P.

`(-1)/3, 0, 1/3, 2/3, ...`

Exercise 2.5 | Q 1. (v) | Page 61

Check whether the following sequence is in A.P.

1, –1, 1, –1, 1, –1, …

Exercise 2.5 | Q 2. (i) | Page 61

First term a and common difference d are given below. Find the corresponding A.P.

a = 5, d = 6

Exercise 2.5 | Q 2. (ii) | Page 61

First term a and common difference d are given below. Find the corresponding A.P.

a = 7, d = – 5

Exercise 2.5 | Q 2. (iii) | Page 61

First term a and common difference d are given below. Find the corresponding A.P.

a = `3/4`, d = `1/2`

Exercise 2.5 | Q 3. (i) | Page 62

Find the first term and common difference of the Arithmetic Progressions whose nth term is given below

tn = – 3 + 2n

Exercise 2.5 | Q 3. (ii) | Page 62

Find the first term and common difference of the Arithmetic Progressions whose nth term is given below

tn = 4 – 7n

Exercise 2.5 | Q 4 | Page 62

Find the 19th term of an A.P. – 11, – 15, – 19, ...

Exercise 2.5 | Q 5 | Page 62

Which term of an A.P. 16, 11, 6, 1, ... is – 54?

Exercise 2.5 | Q 6 | Page 62

Find the middle term(s) of an A.P. 9, 15, 21, 27, …, 183.

Exercise 2.5 | Q 7 | Page 62

If nine times ninth term is equal to the fifteen times fifteenth term, show that six times twenty fourth term is zero

Exercise 2.5 | Q 8 | Page 62

If 3 + k, 18 – k, 5k + 1 are in A.P. then find k

Exercise 2.5 | Q 9 | Page 62

Find x, y and z, given that the numbers x, 10, y, 24, z are in A.P.

Exercise 2.5 | Q 10 | Page 62

In a theatre, there are 20 seats in the front row and 30 rows were allotted. Each successive row contains two additional seats than its front row. How many seats are there in the last row?

Exercise 2.5 | Q 11 | Page 62

The sum of three consecutive terms that are in A.P. is 27 and their product is 288. Find the three terms

Exercise 2.5 | Q 12 | Page 62

The ratio of 6th and 8th term of an A.P. is 7:9. Find the ratio of 9th term to 13th term

Exercise 2.5 | Q 13 | Page 62

In the winter season let us take the temperature of Ooty from Monday to Friday to be in A.P. The sum of temperatures from Monday to Wednesday is 0°C and the sum of the temperatures from Wednesday to Friday is 18°C. Find the temperature on each of the five days.

Exercise 2.5 | Q 14 | Page 62

Priya earned ₹ 15,000 in the first month. Thereafter her salary increased by ₹ 1500 per year. Her expenses are ₹ 13,000 during the first year and the expenses increase by ₹ 900 per year. How long will it take for her to save ₹ 20,000 per month

Exercise 2.6 [Page 67]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.6 [Page 67]

Exercise 2.6 | Q 1. (i) | Page 67

Find the sum of the following

3, 7, 11, … up to 40 terms

Exercise 2.6 | Q 1. (ii) | Page 67

Find the sum of the following

102, 97, 92, … up to 27 terms.

Exercise 2.6 | Q 1. (iii) | Page 67

Find the sum of the following

6 + 13 + 20 + .... + 97

Exercise 2.6 | Q 2 | Page 67

How many consecutive odd integers beginning with 5 will sum to 480?

Exercise 2.6 | Q 3 | Page 67

Find the sum of first 28 terms of an A.P. whose nth term is 4n – 3

Exercise 2.6 | Q 4 | Page 67

The sum of first n terms of a certain series is given as 2n2 – 3n. Show that the series is an A.P.

Exercise 2.6 | Q 5 | Page 67

The 104th term and 4th term of an A.P. are 125 and 0. Find the sum of first 35 terms

Exercise 2.6 | Q 6 | Page 67

Find the sum of all odd positive integers less than 450

Exercise 2.6 | Q 7 | Page 67

Find the sum of all natural numbers between 602 and 902 which are not divisible by 4.

Exercise 2.6 | Q 8. (i) | Page 67

Raghu wish to buy a laptop. He can buy it by paying ₹ 40,000 cash or by giving it in 10 installments as ₹ 4800 in the first month, ₹ 4750 in the second month, ₹ 4700 in the third month and so on. If he pays the money in this fashion, find total amount paid in 10 installments

Exercise 2.6 | Q 8. (ii) | Page 67

Raghu wish to buy a laptop. He can buy it by paying ₹ 40,000 cash or by giving it in 10 installments as ₹ 4800 in the first month, ₹ 4750 in the second month, ₹ 4700 in the third month and so on. If he pays the money in this fashion, find how much extra amount that he has to pay than the cost?

Exercise 2.6 | Q 9 | Page 67

A man repays a loan of ₹ 65,000 by paying ₹ 400 in the first month and then increasing the payment by ₹ 300 every month. How long will it take for him to clear the loan?

Exercise 2.6 | Q 10. (i) | Page 67

A brick staircase has a total of 30 steps. The bottom step requires 100 bricks. Each successive step requires two bricks less than the previous step

How many bricks are required for the top most step?

Exercise 2.6 | Q 10. (ii) | Page 67

A brick staircase has a total of 30 steps. The bottom step requires 100 bricks. Each successive step requires two bricks less than the previous step

How many bricks are required to build the stair case?

Exercise 2.6 | Q 11 | Page 67

If S1, S2 , S3, …., Sm are the sums of n terms of m A.P.'s whose first terms are 1, 2, 3, ……, m and whose common differences are 1, 3, 5, …., (2m – 1) respectively, then show that S1 + S2 + S3 + ... + Sm = `1/2` mn(mn + 1)

Exercise 2.6 | Q 12 | Page 67

Find the sum `[("a" - "b")/("a" + "b") + (3"a" - 2"b")/("a" +  "b") + (5"a" - 3"b")/("a" + "b") + ...  "to"  12  "terms"]`

Exercise 2.7 [Pages 72 - 73]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.7 [Pages 72 - 73]

Exercise 2.7 | Q 1. (i) | Page 72

Identify the following sequence is in G.P.?

3, 9, 27, 81, …

Exercise 2.7 | Q 1. (ii) | Page 72

Identify the following sequence is in G.P.?

4, 44, 444, 4444, .....

Exercise 2.7 | Q 1. (iii) | Page 72

Identify the following sequence is in G.P.?

0.5, 0.05, 0.005, …

Exercise 2.7 | Q 1. (iv) | Page 72

Identify the following sequence is in G.P.?

`1/3, 1/6, 1/12, ...`

Exercise 2.7 | Q 1. (v) | Page 72

Identify the following sequence is in G.P.?

1, −5, 25, −125, ...

Exercise 2.7 | Q 1. (vi) | Page 72

Identify the following sequence is in G.P.?

120, 60, 30, 18, …

Exercise 2.7 | Q 1. (vii) | Page 72

Identify the following sequence is in G.P.?

`16, 4, 1, 1/4,...`

Exercise 2.7 | Q 2. (i) | Page 72

Write the first three terms of the G.P. whose first term and the common ratio are given below

a = 6, r = 3

Exercise 2.7 | Q 2. (ii) | Page 72

Write the first three terms of the G.P. whose first term and the common ratio are given below

a = `sqrt(2)`, r = `sqrt(2)`

Exercise 2.7 | Q 2. (iii) | Page 72

Write the first three terms of the G.P. whose first term and the common ratio are given below

a = 1000, r = `2/5`

Exercise 2.7 | Q 3 | Page 72

In a G.P. 729, 243, 81, … find t7

Exercise 2.7 | Q 4 | Page 72

Find x so that x + 6, x + 12 and x + 15 are consecutive terms of a Geometric Progression

Exercise 2.7 | Q 5. (i) | Page 72

Find the number of terms in the following G.P.

4, 8, 16, …, 8192?

Exercise 2.7 | Q 5. (ii) | Page 72

Find the number of terms in the following G.P.

`1/3, 1/9, 1/27, ..., 1/2187`

Exercise 2.7 | Q 6 | Page 73

In a G.P. the 9th term is 32805 and 6th term is 1215. Find the 12th term

Exercise 2.7 | Q 7 | Page 73

Find the 10th term of a G.P. whose 8th term is 768 and the common ratio is 2

Exercise 2.7 | Q 8 | Page 73

If a, b, c is in A.P. then show that 3a, 3b, 3c  is in G.P.

Exercise 2.7 | Q 9 | Page 73

In a G.P. the product of three consecutive terms is 27 and the sum of the product of two terms taken at a time is `57/2`. Find the three terms

Exercise 2.7 | Q 10 | Page 73

A man joined a company as Assistant Manager. The company gave him a starting salary of ₹ 60,000 and agreed to increase his salary 5% annually. What will be his salary after 5 years?

Exercise 2.7 | Q 11 | Page 73

Sivamani is attending an interview for a job and the company gave two offers to him. Offer A: ₹ 20,000 to start with followed by a guaranteed annual increase of 6% for the first 5 years. Offer B: ₹ 22,000 to start with followed by a guaranteed annual increase of 3% for the first 5 years

Exercise 2.7 | Q 12 | Page 73

If a, b, c is three consecutive terms of an A.P. and x, y, z are three consecutive terms of a G.P. then prove that xb–c × yc–a × za–b = 1

Exercise 2.8 [Page 76]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.8 [Page 76]

Exercise 2.8 | Q 1. (i) | Page 76

Find the sum of first n terms of the G.P.

`5, -3, 9/5, - 27/25, ...`

Exercise 2.8 | Q 1. (ii) | Page 76

Find the sum of first n terms of the G.P.

256, 64, 16, …

Exercise 2.8 | Q 2 | Page 76

Find the sum of first six terms of the G.P. 5, 15, 45, …

Exercise 2.8 | Q 3 | Page 76

Find the first term of the G.P. whose common ratio 5 and whose sum to first 6 terms is 46872

Exercise 2.8 | Q 4. (i) | Page 76

Find the sum to infinity of 9 + 3 + 1 + ….

Exercise 2.8 | Q 4. (ii) | Page 76

Find the sum to infinity of `21 + 14 + 28/3 + ...`

Exercise 2.8 | Q 5 | Page 76

If the first term of an infinite G.P. is 8 and its sum to infinity is `32/3` then find the common ratio

Exercise 2.8 | Q 6. (i) | Page 76

Find the sum to n terms of the series

0.4 + 0.44 + 0.444 + …… to n terms

Exercise 2.8 | Q 6. (ii) | Page 76

Find the sum to n terms of the series

3 + 33 + 333 + ………… to n terms

Exercise 2.8 | Q 7 | Page 76

Find the sum of the Geometric series 3 + 6 + 12 + …….. + 1536

Exercise 2.8 | Q 8 | Page 76

Kumar writes a letter to four of his friends. He asks each one of them to copy the letter and mail to four different persons with the instruction that they continue the process similarly. Assuming that the process is unaltered and it costs ₹ 2 to mail one letter, find the amount spent on postage when 8th set of letters is mailed

Exercise 2.8 | Q 9 | Page 76

Find the rational form of the number `0.bar(123)`

Exercise 2.8 | Q 10 | Page 76

If Sn = (x + y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3) + ... n terms then prove that (x – y)Sn = `[(x^2(x^"n" - 1))/(x - 1) - (y^2(y^"n" - 1))/(y - 1)]`

Exercise 2.9 [Page 81]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.9 [Page 81]

Exercise 2.9 | Q 1. (i) | Page 81

Find the sum of the following series

1 + 2 + 3 + ... + 60

Exercise 2.9 | Q 1. (ii) | Page 81

Find the sum of the following series

3 + 6 + 9 + ... + 96

Exercise 2.9 | Q 1. (iii) | Page 81

Find the sum of the following series

51 + 52 + 53 + ... + 92

Exercise 2.9 | Q 1. (iv) | Page 81

Find the sum of the following series

1 + 4 + 9 + 16 + ... + 225

Exercise 2.9 | Q 1. (v) | Page 81

Find the sum of the following series

62 + 72 + 82 + ... + 212

Exercise 2.9 | Q 1. (vi) | Page 81

Find the sum of the following series

103 + 113 + 123 + ... + 203

Exercise 2.9 | Q 1. (vii) | Page 81

Find the sum of the following series

1 + 3 + 5 + ... + 71

Exercise 2.9 | Q 2 | Page 81

If 1 + 2 + 3 + ... + k = 325, then find 13 + 23 + 33 + ... + k

Exercise 2.9 | Q 3 | Page 81

If 13 + 23 + 33 + ... + k3 = 44100 then find 1 + 2 + 3 + ... + k

Exercise 2.9 | Q 4 | Page 81

How many terms of the series 13 + 23 + 33 + … should be taken to get the sum 14400?

Exercise 2.9 | Q 5 | Page 81

The sum of the cubes of the first n natural numbers is 2025, then find the value of n

Exercise 2.9 | Q 6 | Page 81

Rekha has 15 square colour papers of sizes 10 cm,11 cm,12 cm, …, 24 cm. How much area can be decorated with these colour papers?

Exercise 2.9 | Q 7. (i) | Page 81

Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to n terms

Exercise 2.9 | Q 7. (ii) | Page 81

Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to 8 terms

Exercise 2.10 [Pages 82 - 83]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Exercise 2.10 [Pages 82 - 83]

Multiple choice questions

Exercise 2.10 | Q 1 | Page 82

Euclid’s division lemma states that for positive integers a and b, there exist unique integers q and r such that a = bq + r, where r must satisfy

  • 1 < r < b

  • 0 < r < b

  • 0 ≤ r < b

  • 0 < r ≤ b

Exercise 2.10 | Q 2 | Page 82

Using Euclid’s division lemma, if the cube of any positive integer is divided by 9 then the possible remainders are

  • 0, 1, 8

  • 1, 4, 8

  • 0, 1, 3

  • 1, 3, 5

Exercise 2.10 | Q 3 | Page 82

If the H.C.F of 65 and 117 is expressible in the form of 65m – 117, then the value of m is

  • 4

  • 2

  • 1

  • 3

Exercise 2.10 | Q 4 | Page 82

The sum of the exponents of the prime factors in the prime factorization of 1729 is

  • 1

  • 2

  • 3

  • 4

Exercise 2.10 | Q 5 | Page 82

The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is

  • 2025

  • 5220

  • 5025

  • 2520

Exercise 2.10 | Q 6 | Page 82

74k ≡ _____ (mod 100)

  • 1

  • 2

  • 3

  • 4

Exercise 2.10 | Q 7 | Page 82

Given F1 = 1, F2 = 3 and Fn = Fn–1 + Fn–2 then F5 is

  • 3

  • 5

  • 8

  • 11

Exercise 2.10 | Q 8 | Page 82

The first term of an arithmetic progression is unity and the common difference is 4. Which of the following will be a term of this A.P.

  • 4551

  • 10091

  • 7881

  • 13531

Exercise 2.10 | Q 9 | Page 82

If 6 times of 6th term of an A.P. is equal to 7 times the 7th term, then the 13th term of the A.P. is

  • 0

  • 6

  • 7

  • 13

Exercise 2.10 | Q 10 | Page 82

An A.P. consists of 31 terms. If its 16th term is m, then the sum of all the terms of this A.P. is

  • 16 m

  • 62 m

  • 31 m

  • `31/2` m

Exercise 2.10 | Q 11 | Page 82

In an A.P., the first term is 1 and the common difference is 4. How many terms of the A.P. must be taken for their sum to be equal to 120?

  • 6

  • 7

  • 8

  • 9

Exercise 2.10 | Q 12 | Page 82

If A = 265 and B = 264 + 263 + 262 …. + 20 identify of the following is true?

  • B is 264 more than A

  • A and B are equal

  • B is larger than A by 1

  • A is larger than B by 1

Exercise 2.10 | Q 13 | Page 83

The next term of the sequence `3/16, 1/8, 1/12, 1/18, ...` is

  • `1/24`

  • `1/27`

  • `2/3`

  • `1/81`

Exercise 2.10 | Q 14 | Page 83

If the sequence t1, t2, t3 … is in A.P. then the sequence t6, t12, t18 … is

  • a Geometric Progression

  • an Arithmetic Progression

  • neither an Arithmetic Progression nor a Geometric Progression

  • a constant sequence

Exercise 2.10 | Q 15 | Page 83

The value of (13 + 23 + 33 + ... + 153) – (1 + 2 + 3 + ... + 15) is

  • 14400

  • 14200

  • 14280

  • 14520

Unit Exercise – 2 [Page 83]

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board 2 Numbers and Sequences Unit Exercise – 2 [Page 83]

Unit Exercise – 2 | Q 1 | Page 83

Prove that n2 – n divisible by 2 for every positive integer n

Unit Exercise – 2 | Q 2. (i) | Page 83

A milk man has 175 litres of cow’s milk and 105 litres of buffalow’s milk. He wishes to sell the milk by filling the two types of milk in cans of equal capacity. Calculate the following :

Capacity of a can

Unit Exercise – 2 | Q 2 (ii) | Page 83

A milk man has 175 litres of cow’s milk and 105 litres of buffalow’s milk. He wishes to sell the milk by filling the two types of milk in cans of equal capacity. Calculate the following :

Number of cans of cow’s milk

Unit Exercise – 2 | Q 2. (iii) | Page 83

A milk man has 175 litres of cow’s milk and 105 litres of buffalow’s milk. He wishes to sell the milk by filling the two types of milk in cans of equal capacity. Calculate the following :

Number of cans of buffalow’s milk

Unit Exercise – 2 | Q 3 | Page 83

When the positive integers a, b and c are divided by 13 the respective remainders is 9, 7 and 10. Find the remainder when a b + + 2 3c is divided by 13

Unit Exercise – 2 | Q 4 | Page 83

Show that 107 is of the form  4q +3 for any integer q

Unit Exercise – 2 | Q 5 | Page 83

If (m + 1)th term of an A.P. is twice the (n + 1)th term, then prove that (3m + 1)th term is twice the (m + n + 1)th term

Unit Exercise – 2 | Q 6 | Page 83

Find the 12th term from the last term of the A.P – 2, – 4, – 6, … – 100

Unit Exercise – 2 | Q 7 | Page 83

Two A.P.’s have the same common difference. The first term of one A.P. is 2 and that of the other is 7. Show that the difference between their 10th terms is the same as the difference between their 21st terms, which is the same as the difference between any two corresponding terms.

Unit Exercise – 2 | Q 8 | Page 83

A man saved ₹ 16500 in ten years. In each year after the first, he saved ₹ 100 more than he did in the preceding year. How much did he save in the first year?

Unit Exercise – 2 | Q 9 | Page 83

Find the G.P. in which the 2nd term is `sqrt(6)` and the 6th term is `9sqrt(6)`

Unit Exercise – 2 | Q 10 | Page 83

The value of a motorcycle depreciates at a rate of 15% per year. What will be the value of the motorcycle for 3 year hence, which is now purchased for ₹ 45,000?

Solutions for 2: Numbers and Sequences

Exercise 2.1Exercise 2.2Exercise 2.3Exercise 2.4Exercise 2.5Exercise 2.6Exercise 2.7Exercise 2.8Exercise 2.9Exercise 2.10Unit Exercise – 2
Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board chapter 2 - Numbers and Sequences - Shaalaa.com

Samacheer Kalvi solutions for Mathematics [English] Class 10 SSLC TN Board chapter 2 - Numbers and Sequences

Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Mathematics [English] Class 10 SSLC TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Mathematics [English] Class 10 SSLC TN Board Tamil Nadu Board of Secondary Education 2 (Numbers and Sequences) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Mathematics [English] Class 10 SSLC TN Board chapter 2 Numbers and Sequences are Introduction of Numbers and Sequences, Euclid’s Division Lemma, Euclid’s Division Algorithm, Fundamental Theorem of Arithmetic, Modular Arithmetic, Sequence, Arithmetic Progression, Series, Geometric Progression, Sum to n Terms of a Geometric Progression, Special Series.

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Get the free view of Chapter 2, Numbers and Sequences Mathematics [English] Class 10 SSLC TN Board additional questions for Mathematics Mathematics [English] Class 10 SSLC TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.

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