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Question
Find the sum of the following series
1 + 2 + 3 + ... + 60
Solution
1 + 2 + 3 + ... + 60
`sum_1^"n" "n" = ("n"("n" + 1))/2`
1 + 2 + 3 + ... + 60 = `sum_1^60 "n"`
= `(60(60 + 1))/2`
= 30 × 61
= 1830
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