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Question
Find the sum of the following series
1 + 3 + 5 + ... + 71
Solution
1 + 3 + 5 + ... + 71
= n2
n = `("l" - "a")/"d" + 1`
⇒ `((71 - 1)/2) + 1`
= `70/2 + 1`
= 36
∴ 1 + 3 + 5 + ... + 71 = (36)2
= 1296
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