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Question
Find the 19th term of an A.P. – 11, – 15, – 19, ...
Solution
A.P = – 11, – 15, – 19, ...
a = – 11
d = t2 – t1 = – 15 – (– 11)
= – 15 + 11
= – 4
n = 19
∴ tn = a + (n – 1)d
t19 = – 11 + (19 – 1)(– 4)
= – 11 + 18 × – 4
= – 11 – 72
= – 83
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