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Question
is the Consider the expression an = 3n2 + 1,AP .
Solution
Consider the expression an = 3n2 + 1,
For n = 1, a1 = 3(12) + 1 = 8
For n = 2, a2 = 3(22) + 1 = 17
For n = 3, a3 = 3(32) + 1 = 32
For n = 4, a4 = 3(42) + 1 = 53
The first four terms are 8, 17, 32, 53.
The difference between each consecutive is not same.
Hence this is not an A.P.
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