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प्रश्न
is the Consider the expression an = 3n2 + 1,AP .
उत्तर
Consider the expression an = 3n2 + 1,
For n = 1, a1 = 3(12) + 1 = 8
For n = 2, a2 = 3(22) + 1 = 17
For n = 3, a3 = 3(32) + 1 = 32
For n = 4, a4 = 3(42) + 1 = 53
The first four terms are 8, 17, 32, 53.
The difference between each consecutive is not same.
Hence this is not an A.P.
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संबंधित प्रश्न
If k, 2k- 1 and 2k + 1 are three consecutive terms of an A.P., the value of k is
(A) 2
(B) 3
(C) -3
(D) 5
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