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Question
Write the first three terms of the G.P. whose first term and the common ratio are given below
a = `sqrt(2)`, r = `sqrt(2)`
Solution
a = `sqrt(2)`, r = `sqrt(2)`
tn = arn–1
t1 = ar1–1 = ar0 = `sqrt(2) xx 1 = sqrt(2)`
t2 = ar2–1 = ar1 = `sqrt(2) xx sqrt(2)` = 2
t3 = ar3–1 = ar2 = `sqrt(2) xx (sqrt(2))^2`
= `sqrt(2) xx 2 = 2sqrt(2)`
∴ The 3 terms are `sqrt(2), 2, 2sqrt(2), ...`
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