Advertisements
Advertisements
Question
Write the first three terms of the G.P. whose first term and the common ratio are given below
a = 1000, r = `2/5`
Solution
a = 1000, r = `2/5`
tn = arn-1
t1 = ar1-1 = ar0 = 1000 × 1 = 1000
t2 = ar2-1 = ar = `1000 xx 2/5` = 400
t3 = ar3-1 = ar2 = `1000 (2/5)^2`
= `1000 xx 4/25`
= 160
∴ The 3 terms are 1000, 400, 160, …
APPEARS IN
RELATED QUESTIONS
Identify the following sequence is in G.P.?
3, 9, 27, 81, …
Identify the following sequence is in G.P.?
`1/3, 1/6, 1/12, ...`
Identify the following sequence is in G.P.?
1, −5, 25, −125, ...
Identify the following sequence is in G.P.?
`16, 4, 1, 1/4,...`
Write the first three terms of the G.P. whose first term and the common ratio are given below
a = 6, r = 3
Write the first three terms of the G.P. whose first term and the common ratio are given below
a = `sqrt(2)`, r = `sqrt(2)`
In a G.P. 729, 243, 81, … find t7
Find the number of terms in the following G.P.
4, 8, 16, …, 8192?
If a, b, c is in A.P. then show that 3a, 3b, 3c is in G.P.
If a, b, c is three consecutive terms of an A.P. and x, y, z are three consecutive terms of a G.P. then prove that xb–c × yc–a × za–b = 1
