Advertisements
Advertisements
Question
Find the nth term of the following sequence
`0, 1/2, 2/3, ...`
Solution
`0, 1/2, 2/3, ...`
= `(1 - 1)/1, (2 - 1)/2, (3 - 1)/3 .......`
⇒ `("n" - 1)/"n"`
∴ nth term is `("n" - 1)/"n"`
APPEARS IN
RELATED QUESTIONS
Find the next three terms of the following sequence.
5, 1, – 3, …
Find the first four terms of the sequence whose nth terms are given by an = n3 – 2
Find the first four terms of the sequence whose nth terms are given by an = (–1)n+1 n(n + 1)
Find the first four terms of the sequences whose nth terms are given by an = 2n2 – 6
Find the indicated terms of the sequences whose nth terms are given by
an = `(5"n")/("n" + 2)`; a6 and a13
Find the indicated terms of the sequences whose nth terms are given by
an = – (n2 – 4); a4 and a11
Find a8 and a15 whose nth term is an = `{{:(("n"^2 - 1)/("n" + 3)";", "n is even""," "n ∈ N"),(("n"^2)/(2"n" + 1)";", "n is odd""," "n ∈ N"):}`
If a1 = 1, a2 = 1 and an = 2an−1 + an−2, n ≥ 3, n ∈ N, then find the first six terms of the sequence
Given F1 = 1, F2 = 3 and Fn = Fn–1 + Fn–2 then F5 is
The next term of the sequence `3/16, 1/8, 1/12, 1/18, ...` is