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Question
Find the first four terms of the sequence whose nth terms are given by an = n3 – 2
Solution
tn = an = n3 – 2
a1 = 13 – 2 = 1 – 2 = – 1
a2 = 23 – 2 = 8 – 2 = 6
a3 = 33 – 2 = 27 – 2 = 25
a4 = 43 – 2 = 64 – 2 = 62
∴ The first four terms are – 1, 6, 25, 62, ……….
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