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प्रश्न
In an electron microscope, the electrons are accelerated by a voltage of 14 kV. If the voltage is changed to 224 kV, then the de Broglie wavelength associated with the electrons would
पर्याय
increase by 2 times
decrease by 2 times
decrease by 4 times
increase by 4 times
उत्तर
decrease by 4 times
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संबंधित प्रश्न
Write the expression for the de Broglie wavelength associated with a charged particle of charge q and mass m, when it is accelerated through a potential V.
State de Broglie hypothesis.
A proton and an electron have the same kinetic energy. Which one has a greater de Broglie wavelength? Justify.
Write the relationship of de Broglie wavelength λ associated with a particle of mass m in terms of its kinetic energy K.
What is Bremsstrahlung?
Explain why photoelectric effect cannot be explained on the basis of wave nature of light.
How do we obtain characteristic x-ray spectra?
Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to 81.9 × 10–15 J.
(Given: mass of proton is 1836 times that of electron).
A deuteron and an alpha particle are accelerated with the same potential. Which one of the two has
- greater value of de Broglie wavelength associated with it and
- less kinetic energy?
Explain.
The ratio between the de Broglie wavelength associated with proton accelerated through a potential of 512 V and that of alpha particle accelerated through a potential of X volts is found to be one. Find the value of X.
