मराठी

In Figure, ∠BAC = 90° and AD ⊥ BC. Then, ______. - Mathematics

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प्रश्न

In Figure, ∠BAC = 90° and AD ⊥ BC. Then, ______.

पर्याय

  • BD . CD = BC2

  • AB . AC = BC2

  • BD . CD = AD2

  • AB . AC = AD2

MCQ
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उत्तर

In Figure, ∠BAC = 90° and AD ⊥ BC. Then, BD . CD = AD2.

Explanation:


From ∆ADB and ∆ADC,

According to the question, we have,

∠D = ∠D = 90°  ...(∵ AD ⊥ BC)

∠DBA = ∠DAC  ...[Each angle = 90° – ∠C]

Using AAA similarity criteria,

∆ADB ∼ ∆ADC

`("BD")/("AD") = ("AD")/("CD")`

BD . CD = AD2

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पाठ 6: Triangles - Exercise 6.1 [पृष्ठ ६०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
पाठ 6 Triangles
Exercise 6.1 | Q 1 | पृष्ठ ६०

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