Advertisements
Advertisements
प्रश्न
In the following, find the value of k for which the given value is a solution of the given equation:
x2 + 3ax + k = 0, x = -a
उत्तर
We are given here that,
x2 + 3ax + k = 0, x = -a
Now, as we know that x = -a is a solution of the quadratic equation, hence it should satisfy the equation. Therefore substituting x = -a in the above equation gives us,
x2 + 3ax + k = 0
(-a)2 + 3a(-a) + k =0
a2 - 3a2 + k = 0
-2a2 + k = 0
k = 2a2
Hence the value of k = 2a2.
APPEARS IN
संबंधित प्रश्न
Check whether the following is the quadratic equation:
x2 - 2x = (-2)(3 - x)
Solve the equation 4x2 – 5x – 3 = 0 and give your answer correct to two decimal places
Solve `((2x - 3)/(x -1)) - 4((x - 1)/(2x - 3)) = 3`
Which of the following are quadratic equation in x?
`x^2-x-3=0`
`2/x^2-5/x+2=0`
`16/x-1=15/(x+1),x≠0,-1`
Solve for x the quadratic equation x2 - 4x - 8 = 0.
Give your answer correct to three significant figures.
The time taken by a person to cover 150kms was 2.5 hrs more than the time taken in the return j ourney. If he returned at a speed of 10km/ h more than the speed when going, find his speed per hour in each direction.
If x = −3 and x = `2/3` are solutions of quadratic equation mx2 + 7x + n = 0, find the values of m and n.
In each of the following find the values of k of which the given value is a solution of the given equation:
x2 - x(a + b) + k = 0, x = a
