मराठी

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base? - Mathematics

Advertisements
Advertisements

प्रश्न

In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

बेरीज

उत्तर

Let the parts of red pigment required to mix with 1800 mL of base be x.

The given information, in the form of a table, is as follows:

Parts of red pigment 1 x
Parts of base (in mL) 75 1800

The parts of red pigment and the parts of the base are in direct proportion.

Therefore, we obtain

`1/75 = x/1800`

=> x = `(1 xx 1800)/75`

=> x = 24

Thus, 24 parts of red pigments should be mixed with 1800 mL of base.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Direct and Inverse Proportions - Exercise 13.1 [पृष्ठ २०८]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 8
पाठ 13 Direct and Inverse Proportions
Exercise 13.1 | Q 3 | पृष्ठ २०८

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×