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Question
In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?
Solution
Let the parts of red pigment required to mix with 1800 mL of base be x.
The given information, in the form of a table, is as follows:
| Parts of red pigment | 1 | x |
| Parts of base (in mL) | 75 | 1800 |
The parts of red pigment and the parts of the base are in direct proportion.
Therefore, we obtain
`1/75 = x/1800`
=> x = `(1 xx 1800)/75`
=> x = 24
Thus, 24 parts of red pigments should be mixed with 1800 mL of base.
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