Advertisements
Advertisements
प्रश्न
In a school, students decided to plant trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be double of the class in which they are studying. If there are 1 to 12 classes in the school and each class has two sections, find how many trees were planted by the students.
उत्तर
Let a be the first term and d be the common difference.
We know that, sum of first n terms = Sn = \[\frac{n}{2}\][2a + (n − 1)d]
It can be observed that the number of trees planted by the students forms an A.P.
2, 4, 6, 8, ... , 24
Here, a = 2, d = 2 and n = 12.
= 6(26)
= 156
Therefore, trees planted by 1 section of all the classes = 156.
Number of trees planted by 2 sections of all the classes = 2 × 156 = 312
Thus, 312 trees were planted by the students.
APPEARS IN
संबंधित प्रश्न
In an A.P., if the first term is 22, the common difference is −4 and the sum to n terms is 64, find n.
The first and last terms of an AP are a and l respectively. Show that the sum of the nth term from the beginning and the nth term form the end is ( a + l ).
Find the three numbers in AP whose sum is 15 and product is 80.
The first three terms of an AP are respectively (3y – 1), (3y + 5) and (5y + 1), find the value of y .
The next term of the A.P. \[\sqrt{7}, \sqrt{28}, \sqrt{63}\] is ______.
Choose the correct alternative answer for the following question .
The sequence –10, –6, –2, 2,...
The sum of first n terms of an A.P is 5n2 + 3n. If its mth terms is 168, find the value of m. Also, find the 20th term of this A.P.
The common difference of the A.P.
Find the sum of first 10 terms of the A.P.
4 + 6 + 8 + .............
Find the sum:
1 + (–2) + (–5) + (–8) + ... + (–236)