मराठी

In a Survey of 600 Students in a School, 150 Students Were Found to Be Taking Tea and 225 Taking Coffee, 100 Were Taking Both Tea and Coffee. Find How Many Students Were Taking Neither Tea Nor Coffee? - Mathematics

Advertisements
Advertisements

प्रश्न

In a survey of 600 students in a school, 150 students were found to be taking tea and 225 taking coffee, 100 were taking both tea and coffee. Find how many students were taking neither tea nor coffee?

बेरीज

उत्तर

Let U be the set of all students who took part in the survey.

Let T be the set of students taking tea.

Let C be the set of students taking coffee.

Accordingly, n(U) = 600, n(T) = 150, n(C) = 225, n(T ∩ C) = 100

To find: Number of student taking neither tea nor coffee i.e., we have to find n(T' ∩ C').

n(T' ∩ C') = n(T ∪ C)'

n(U) – n(T ∪ C)

n(U) – [n(T) + n(C) – n(T ∩ C)]

= 600 – [150 + 225 – 100]

= 600 – 275

= 325

Hence, 325 students were taking neither tea nor coffee.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Sets - Miscellaneous Exercise [पृष्ठ २७]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 1 Sets
Miscellaneous Exercise | Q 13 | पृष्ठ २७

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the intersection of pair of sets:

X = {1, 3, 5}, Y = {1, 2, 3}


Find the intersection of pair of sets:

A = {a, e, i, o, u}, B = {a, b, c}


Find the intersection of pair of sets:

A = {x : x is a natural number and multiple of 3}

B = {x : x is a natural number less than 6}


Find the intersection of pair of sets:

A = {1, 2, 3}, B = Φ


If A = {x : x is a natural number}, B = {x : x is an even natural number} C = {x : x is an odd natural number} and D = {x : x is a prime number}, find:

A ∩ B


Let A, B and C be the sets such that A ∪ B = A ∪ C and A ∩ B = A ∩ C. Show that B = C.


Show that the following four conditions are equivalent:

  1. A ⊂ B
  2. A – B = Φ
  3. A ∪ B = B 
  4. A ∩ B = A

Using properties of sets show that A ∪ (A ∩ B) = A


Using properties of sets show that A ∩ (A ∪ B) = A.


Show that A ∩ B = A ∩ C need not imply B = C.


Let A and B be sets. If A ∩ X = B ∩ X = Φ and A ∪ X = B ∪ X for some set X, show that A = B.

(Hints A = A ∩ (A ∪ X), B = B ∩ (B ∪ X) and use distributive law)


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

B ∩ C


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

A ∩ C ∩ D


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

A ∩ C


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

B ∩ D


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

A ∩ (B ∪ C)


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

A ∩ D


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

A ∩ (B ∪ D)


If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find

(A ∪ D) ∩ (B ∪ C)


If A = {x : x is a natural number}, B = {x : x is an even natural number} C = {x : x is an odd natural number} and D = {x : x is a prime number}, find:

A ∩ C


If A = {x : x is a natural number}, B = {x : x is an even natural number} C = {x : x is an odd natural number} and D = {x : x is a prime number}, find:

A ∩ D


If A = {x : x is a natural number}, B = {x : x is an even natural number} C = {x : x is an odd natural number} and D = {x : x is a prime number}, find:

B ∩ D


If A = {x : x is a natural number}, B = {x : x is an even natural number} C = {x : x is an odd natural number} and D = {x : x is a prime number}, find:

C ∩ D


If X = {a, b, c, d} and Y = {f, b, d, g}, find 

X ∩ Y


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×