Advertisements
Advertisements
प्रश्न
In the following figure, point D divides AB in the ratio 3 : 5. Find :
BC = 4.8 cm, find the length of DE.
उत्तर
Given that `(AD)/(DB) = 3/5`
So, `(AD)/(AB) = 3/8`
In ΔADE and ΔABC,
∠ADE = ∠ABC ...(Since DE || BC, so the angles are corresponding angles)
∠A = ∠A ...(Common angle)
∴ ΔADE ∼ ΔABC ...(AA criterion for similarity)
`=> (AD)/(AB) = (DE)/(BC)`
`=> 3/8 = (DE)/(4.8)`
`=>` DE = 1.8 cm
APPEARS IN
संबंधित प्रश्न
P and Q are points on sides AB and AC respectively of ∆ABC. If AP = 3 cm, PB = 6cm. AQ = 5 cm and QC = 10 cm, show that BC = 3PQ.
Prove that the line segments joining the mid points of the sides of a triangle form four triangles, each of which is similar to the original triangle
Show that ΔABC, where A(–2, 0), B(2, 0), C(0, 2) and ΔPQR where P(–4, 0), Q(4, 0), R(0, 2) are similar triangles
In the given figure, DE║BC. If DE = 3cm, BC = 6cm and ar(ΔADE) = `15cm^2`, find the area of ΔABC.
State the SSS-similarity criterion for similarity of triangles
In Figure 3, ABCD is a trapezium with AB || DC, AB = 18 cm, DC = 32 cm and the distance between AB and DC is 14 cm. If arcs of equal radii 7 cm have been drawn, with centres A,B, C and D, then find the area of the shaded region.
The length of a river in a map is 54cm. if lcm on the map represents 12500m on land, find the length of the river.
Let ∆ ABC ∽ ∆ DEF and their areas be respectively, 64 cm2 and 121 cm2. If EF = 15⋅4 cm, find BC.
A model of cargo tuck is made to a scale of 1:40. The length of the model is 15cm. Calculate: The length of the truck
PR = 26 cm, QR = 24 cm, ∠PAQ = 90°, PA = 6 cm and QA = 8 cm. Find ∠PQR
