Advertisements
Advertisements
प्रश्न
PR = 26 cm, QR = 24 cm, ∠PAQ = 90°, PA = 6 cm and QA = 8 cm. Find ∠PQR
पर्याय
80°
85°
75°
90°
उत्तर
90°
Explanation;
Hint:
PR = 26 cm, QR = 24 cm, ∠PAQ = 90°
In the ∆PQR,
PQ = `sqrt("PR"^2 - "QR"^2)`
= `sqrt(26^2 - 24^2)`
= `sqrt(676 - 576)`
= `sqrt(100)`
= 10
In the right ∆APQ
PQ2 = PA2 + AQ2
= 62 + 82
= 36 + 64
= 100
PQ = `sqrt(100)`
= 10
∆PQR is a right angled triangle at Q.
Since PR2 = PQ2 + QR2
∠PQR = 90°
APPEARS IN
संबंधित प्रश्न
In figure, if ∠A = ∠C, then prove that ∆AOB ~ ∆COD
In an isosceles ∆ABC, the base AB is produced both ways in P and Q such that AP × BQ = AC2 and CE are the altitudes. Prove that ∆ACP ~ ∆BCQ.
Prove that, in a right triangle, the square on the hypotenuse is equal to the sum of the squares on the other two sides.
The given figure shows a triangle PQR in which XY is parallel to QR. If PX : XQ = 1 : 3 and QR = 9 cm, find the length of XY.
Further, if the area of ΔPXY = x cm2; find, in terms of x the area of :
- triangle PQR.
- trapezium XQRY.
In ΔABC, D and E are the mid-point on AB and AC such that DE || BC.
If AD : BD = 4 : 5 and EC = 2.5cm, find AE.
If ΔABC, D and E are points on AB and AC. Show that DE || BC for each of the following case or not:
AD = 5.7cm, BD = 9.5cm, AE = 3.3cm, and EC = 5.5cm
A model of cargo tuck is made to a scale of 1:40. The length of the model is 15cm. Calculate: The base area of the truck, if the base area of the model is 30m2
In the given figure YH || TE. Prove that ΔWHY ~ ΔWET and also find HE and TE
In the given figure, if ΔEAT ~ ΔBUN, find the measure of all angles.
In figure, if PQRS is a parallelogram and AB || PS, then prove that OC || SR.
