मराठी

In the integral daana∫dx(2ax-x2)12=ansin-1(xa-1), the value of n should be ______. -

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प्रश्न

In the integral `int("d"x)/((2"a"x-x^2)^(1/2)) = "a"^"n" sin^-1 (x/"a"-1)`, the value of n should be ______.

पर्याय

  • 1

  • -1

  • 0

  • `1/2`

MCQ

उत्तर

In the integral `int("d"x)/((2"a"x-x^2)^(1/2)) = "a"^"n" sin^-1 (x/"a"-1)`, the value of n should be 0.

Explanation:

`int("d"x)/((2"a"x-x^2)^(1/2)) = "a"^"n" sin^-1 (x/"a"-1)`

From R.H.S. dimension of [a] = [L],

Since `[x/"a"]` should be dimensionless,

Dimension L.H.S.: `["L"]/["L"]` = L° 

Since dimension of [2ax – x2]1/2 = [L]

and dimension of [dx] = L

Equating dimensions of L.H.S. and R.H.S.

L° = Ln

n = 0

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