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प्रश्न
In what ratio is the line joining (2, –4) and (–3, 6) divided by the y-axis?
उत्तर
Let the line joining points A (2, –4) and B (–3, 6) be divided by point P (0, y) in the ratio k : 1.
`x = (kx_2 + x_1)/(k + 1)`
`0 = (k xx (-3) + 1 xx 2)/(k + 1)`
`0 = -3k + 2`
`k = 2/3`
Thus, the required ratio is 2 : 3.
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संबंधित प्रश्न
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= `a(1/t^2 + 1) = (a(t^2 + 1))/t^2`
Now `(1)/"SP" + (1)/"SQ" = (1)/(a(t^2 + 1)) + (1 xx t^2)/(a(t^2 + 1)`
= `((1 + t^2))/(a(t^2 + 1)`
`(1)/"SP" + (1)/"SQ" = (1)/a`.
In the following figure line APB meets the X-axis at A, Y-axis at B. P is the point (4, -2) and AP: PB = 1: 2. Write down the coordinates of A and B.